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Answer on question #52311, Physics, Quantum Mechanics
Question Which of the following is NOT correct?
k⃗⋅k⃗=1\vec{k} \cdot \vec{k} = 1k⋅k=1
i⃗×j⃗=k⃗\vec{i} \times \vec{j} = \vec{k}i×j=k
i⃗×k⃗=−j⃗\vec{i} \times \vec{k} = -\vec{j}i×k=−j
j⃗⋅j⃗=0\vec{j} \cdot \vec{j} = 0j⋅j=0
Solution j⃗⋅j⃗=0\vec{j} \cdot \vec{j} = 0j⋅j=0 is not correct.
It should be j⃗⋅j⃗=∣j⃗∣2=1\vec{j} \cdot \vec{j} = |\vec{j}|^2 = 1j⋅j=∣j∣2=1 as it is unit vector.
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