Question #52042

Given three vectors
a⃗ =−i⃗ −4j⃗ +2k⃗
,
b⃗ =3i⃗ +2j⃗ −2k⃗
,
c⃗ =2i⃗ −3j⃗ +k⃗
, calculate
a⃗ ⋅(b⃗ ×c⃗ )


−6
6

9


−9

Expert's answer

Answer on question #52042, Physics, Quantum Mechanics

Question Given three vectors a=i4j+2k,b=3i+2j2k,c=2i3j+k\vec{a} = -i - 4j + 2k, \vec{b} = 3i + 2j - 2k, \vec{c} = 2i - 3j + k, calculate a(b×c)\vec{a} \cdot (b \times c)

-6

6

9

-9

Solution To find triple product we have to find determinant of matrix made of coordinates of the vectors,


a(b×c)=142322231=6\vec{a} \cdot (b \times c) = \left| \begin{array}{ccc} -1 & -4 & 2 \\ 3 & 2 & -2 \\ 2 & -3 & 1 \end{array} \right| = 6


Answer is 6.

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