Question

18 The displacement of a particle along the X-axis is given as
x=5t2+1
, where x is in metres and t in seconds. Calculate its average velocity in the time interval between 2 s and 3 s.

21 m/s

40 m/s

46 m/s

25 m/s

Answer 1

Answer on Question#52031, Physics, Quantum Mechanics

We are given $x(t) = 5t^{2} + 1$ .

The average velocity between time $t = 2s$ and $t = 3s$ by definition is $v = \frac{x(3) - x(2)}{3 - 2}$ . The positions are times $t = 2s$ and $t = 3s$ are $x(2) = 21m$ and $x(3) = 46m$ respectively. Plugging in these values into formula for average velocity, obtain $v = \frac{46m - 21m}{1s} = 25\frac{m}{s}$ .