Question #37533

WHAT ARE KET AND BRA VECTORS

Expert's answer

Answer on Question#37533, Physics, Quantum Mechanics.

Bra and ket vectors are notations for quantum states in quantum mechanics, introduced by Dirac. It is known, that in Schrodinger's picture of quantum mechanics, quantum state is given by wave function ψ(x,t)\psi(x,t) , where ψ(x)2=ψ(x)ψ(x)|\psi(x)|^2 = \overline{\psi}(x)\psi(x) is the probability density of a quantum object (particle) in coordinate space.

The inner product ψψ\psi \psi might be rewritten as <ψψ><\psi|\psi> , where ψ>|\psi> is the ket vector and <ψ<\psi| bra vector.

More generally, in Hilbert space, the inner product (in bra-ket notation) is <ψφ>=dxψφ< \psi |\varphi > = \int dx\overline{\psi}\varphi .

If one fixates a basis for wave function, its ket vector ψ|\psi \rangle is simply the vertical column with its

components in this basis: (a1a2an)\left( \begin{array}{l}a_{1}\\ a_{2}\\ \ldots \\ a_{n} \end{array} \right) and bra vector <ψ< \psi | is the transposed and complex conjugate to ket

vector: (a1a2an)\left( \begin{array}{lll}a_{1} & a_{2} & \ldots & a_{n} \end{array} \right) . Hence, inner product is then <ψψ>=i=1naiai=ai2=1< \psi |\psi > = \sum_{i = 1}^{n}a_{i}a_{i} = \sum |a_{i}|^{2} = 1 .

The outer product ψ><ψ|\psi > < \psi| is an operator and is equal to tensor product ψψ\psi \otimes \psi .

The matrix element of an operator in bra-ket notation is, for example <φAψ>< \varphi | A | \psi > . For spin operators commonly used notations are |\uparrow\rangle and |\downarrow\rangle for spin s=12s = \frac{1}{2} states (up and down respectively).


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