At 88 meters high a rock is thrown horizontally from the top of a cliff, with a horizontal speed of 25 m/s. Now, what's the direction of velocity and with what velocity does the rock hit the ground?
vx=25 ms,v_x=25~\frac ms,vx=25 sm,
vy=2gh=41.5 ms,v_y=\sqrt{2gh}=41.5~\frac ms,vy=2gh=41.5 sm,
v=vx2+vy2=48.5 ms,v=\sqrt{v_x^2+v_y^2}=48.5~\frac ms,v=vx2+vy2=48.5 sm,
φ=−arctanvyvx=−59°.\varphi=-\arctan\frac{v_y}{v_x}=-59°.φ=−arctanvxvy=−59°.
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