A rock is thrown horizontally from the top of a cliff 88 m high with a horizontal speed of 25 m/s, what is the direction of velocity?
vx=25 ms,v_x=25~\frac ms,vx=25 sm,
vy=2gh=48 ms,v_y=\sqrt{2gh}=48~\frac ms,vy=2gh=48 sm,
v=vx2+vy2=53.7 ms,v=\sqrt{v_x^2+v_y^2}=53.7~\frac ms,v=vx2+vy2=53.7 sm,
α=−arctanvyvx=−63.4°.\alpha=-\arctan\frac{v_y}{v_x}=-63.4°.α=−arctanvxvy=−63.4°.
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