Question 33177
When alpha-particle is accelerated by potential U=20VU = 20VU=20V , it has energy E=qU=2eUE = qU = 2eUE=qU=2eU (the charge of alpha-particle is q=2eq = 2eq=2e ).
Since the energy of the alpha-particle is E=hν=hcλE = h\nu = \frac{hc}{\lambda}E=hν=λhc , obtain
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