Question #322822

A 64.0 kg person is riding an elevator as shown in the figure above. The elevator is accelerating upwards at a rate of 0.682 m s−2

For this problem use g = 9.81 m s−2 

What is the magnitude of the normal force, the force on the person from the elevator? (in N to 3.s.f)


1
Expert's answer
2022-04-03T16:51:08-0400

F=m(g+a)=671.488 N.F=m(g+a)=671.488~N.


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