Answer to Question #322822 in Quantum Mechanics for komal

Question

A 64.0 kg person is riding an elevator as shown in the figure above. The elevator is accelerating upwards at a rate of 0.682 m s^−2. 

For this problem use g = 9.81 m s^−2 

What is the magnitude of the normal force, the force on the person from the elevator? (in N to 3.s.f)

Answer 1

$F=m(g+a)=671.488~N.$