A quantum particle is moving in a harmonic oscillator potential v(x)=m*omega^(2)*x^(2)/2.
The eigenstates are denoted by |n> while the wave functions are Psi n (x) = <x|n>.
At t=0, the system in the state: |Psi(t=0)>=A*sum from n of (1/sqrt(2))^2 | n >
Find the constant A, obtain the expression for the wave function Psi(x,t) = <x | Psi(t)> at a latter time, calculate the probability density |Psi(x,t)|^2 and the expectation value of the energy.
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Expert's answer
2011-06-09T14:39:58-0400
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