Answer to Question #289922 in Quantum Mechanics for Chiblink

Quantum Mechanics

Question #289922

Evaluate the moment of inertia of a thin rod with axis of rotation at the centre , if its length is 100cm and its mass is 2.3kg.

Expert's answer

"I=\\frac{mL^2}{12}=\\frac{2.3\\cdot 1^2}{12}=0.19~kg\\cdot m^2."

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