Answer to Question #289922 in Quantum Mechanics for Chiblink

Question

Evaluate the moment of inertia of a thin rod with axis of rotation at the centre , if its length is 100cm and its mass is 2.3kg.

Answer 1

$I=\frac{mL^2}{12}=\frac{2.3\cdot 1^2}{12}=0.19~kg\cdot m^2.$