Answer to Question #283268 in Quantum Mechanics for abhi

Quantum Mechanics

Question #283268

If the energy of electron in second excited state is 9eV in an infinite potential box . The ground state energy of the particle is:

Expert's answer

"E_2=E_0(1-\\frac 1{2^2}),\\implies"

"E_0=\\frac 43 E_2=\\frac 43\\cdot 9=12~eV."

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