Answer to Question #281419 in Quantum Mechanics for fsdfsdf

Question

Using Bohr’s theory, calculate the energy required to remove the electron from the ground state of singly ionized helium, that is, helium with one electron already removed.

Answer 1

The energy is

$$E=\frac{13.6Z^2}{n^2}=\frac{13.6·2^2}{1^2}=54.4\text{ eV}.$$