Question #278698

A 400.0-N sign hangs from the end of a uniform strut. The strut is 4.0 m long and

weighs 600.0 N. The strut is supported by a hinge at the wall and by a cable whose

other end is tied to the wall at a point 3.0 m above the left end of the strut. Find the

tension in the supporting cable and the force of the hinge on the strut.


1
Expert's answer
2021-12-13T16:56:09-0500

a)

M=0,    M=0,\implies

6002+40044T35=0,600\cdot 2+400\cdot 4-4T\cdot \frac 35=0,

T=1167 N,T=1167~N,

b)

Fh=45T=933 N,F_h=\frac45T=933~N,

Fv=60024=300 N,F_v=600\cdot \frac 24=300~N,

F=Fh2+Fv2=980 N.F=\sqrt{F_h^2+F_v^2}=980~N.


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