Answer to Question #276354 in Quantum Mechanics for bald

Question

n a jump spike, Mark Angel slams the volleyball from a height of 2.3 m with a speed of 18 m/s at 24° below the horizontal. How far on the opposite side will the ball land?

Answer 1

$$d=\\\frac{18\cos{24}}{9.8}(18\sin{24}+\sqrt{(18\sin{24})^2+2(9.8(2.3)})\\=29\ m$$