Answer to Question #244735 in Quantum Mechanics for Radhika

Question #244735
Ground state energy of a particle in a one dimensional infinite potential box is 2 ev then energy of first excited state is how much
1
Expert's answer
2021-09-30T10:19:46-0400

Energy of a particle in the ground is E1=2.0e.VE_1=2.0 e.V

The energy of a particle in the first excited state is

E2=22×E1=22×(2.0  eV)=8  eVE_2=2^2\times E_1\\ =2^2\times(2.0\; eV)\\ =8 \; eV


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