Question

Determine the wavelength of proton that has been accelerated through a pd of 200V.

Answer 1

Answer

Wavelength of proton can be given as

$\lambda=\frac{h}{\sqrt{2mev}}\\$

$\lambda=\frac{6.62\times10^{-34}}{\sqrt{2(1.67\times10^{-27})(1.6\times10^{-19})(200)}}\\\lambda=202.5nm$