Answer to Question #198016 in Quantum Mechanics for Jillian Montero

Question

A rock is thrown horizontally from the top of a cliff 88 m high, with a horizontal speed of 25 m/s. How far from the base of the cliff does the rock land?

Answer 1

$h=\frac{gt^2}{2}\implies t=\sqrt{\frac{2h}{g}},$

$l=vt=v \sqrt{\frac{2h}{g}}=106~m.$