Question #198016

A rock is thrown horizontally from the top of a cliff 88 m high, with a horizontal speed of 25 m/s. How far from the base of the cliff does the rock land?


Expert's answer

h=gt22    t=2hg,h=\frac{gt^2}{2}\implies t=\sqrt{\frac{2h}{g}},

l=vt=v2hg=106 m.l=vt=v \sqrt{\frac{2h}{g}}=106~m.


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