Answer to Question #198016 in Quantum Mechanics for Jillian Montero

Question #198016

A rock is thrown horizontally from the top of a cliff 88 m high, with a horizontal speed of 25 m/s. How far from the base of the cliff does the rock land?

Expert's answer

$h=\frac{gt^2}{2}\implies t=\sqrt{\frac{2h}{g}},$

$l=vt=v \sqrt{\frac{2h}{g}}=106~m.$

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