Question #189029

A particle trapped in a one-dimensional box of length L is described by the wave function ψ = ax. What is the probability that the particle is lying between L1 and L2?


Expert's answer

By definition, the probability that the particle is lying between L1 and L2 is given as follows (see http://www.iitg.ac.in/asil/QM-02.pdf):


P=∫L1L2∣ψ∣2dxP = \int_{L_1}^{L_2}|\psi|^2dx

where


∣ψ∣2=(ax)2=a2x2|\psi|^2 = (ax)^2 =a^2x^2

is the modulus of the wavefunction. Thus, evaluating the integral, obtain:


P=a2∫L1L2x2dx=a2x33∣L1L2=a23(L23−L13)P = a^2\int_{L_1}^{L_2}x^2dx = a^2\left.\dfrac{x^3}{3}\right |_{L_1}^{L_2} = \dfrac{a^2}{3}(L_2^3-L_1^3)

Answer. P=a23(L23−L13)P = \dfrac{a^2}{3}(L_2^3-L_1^3).


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