Question #189029

A particle trapped in a one-dimensional box of length L is described by the wave function ψ = ax. What is the probability that the particle is lying between L1 and L2?


Expert's answer

By definition, the probability that the particle is lying between L1 and L2 is given as follows (see http://www.iitg.ac.in/asil/QM-02.pdf):


P=L1L2ψ2dxP = \int_{L_1}^{L_2}|\psi|^2dx

where


ψ2=(ax)2=a2x2|\psi|^2 = (ax)^2 =a^2x^2

is the modulus of the wavefunction. Thus, evaluating the integral, obtain:


P=a2L1L2x2dx=a2x33L1L2=a23(L23L13)P = a^2\int_{L_1}^{L_2}x^2dx = a^2\left.\dfrac{x^3}{3}\right |_{L_1}^{L_2} = \dfrac{a^2}{3}(L_2^3-L_1^3)

Answer. P=a23(L23L13)P = \dfrac{a^2}{3}(L_2^3-L_1^3).


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