Two small metal spheres are 30.0 cm apart. The spheres have equal amount of negative charges and repel from each other with a force of 40.0 N. What is the charge on each sphere?
We have,
d=30cm=0.3md= 30cm = 0.3md=30cm=0.3m
F=40NF = 40NF=40N
q1=q2=−qq_1 = q_2 = -qq1=q2=−q
We know,
F=14πϵ0q1q2d2F = \dfrac{1}{4\pi \epsilon_0} \dfrac{q_1q_2}{d^2}F=4πϵ01d2q1q2
After putting values we get,
40=14πϵ0q20.3×0.340 = \dfrac{1}{4\pi\epsilon_0} \dfrac{q^2}{0.3\times 0.3}40=4πϵ010.3×0.3q2
q2=40×4πϵ0×0.3×0.3q^2 = 40\times 4\pi\epsilon_0\times 0.3 \times 0.3q2=40×4πϵ0×0.3×0.3
We get,
q=0.632×10−3Cq = 0.632\times 10^{-3} Cq=0.632×10−3C
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