Answer to Question #168584 in Quantum Mechanics for Richard

Question

The current position of the harmonic oscillator is given by the relation 

x(t)=(0,3m)cos(πt/2).Time t is expressed in seconds. Find the period of the oscillator.

Answer 1

$\omega=\dfrac{\pi}{2}rad/s^{-1}$

$T=\dfrac{2\pi}{\omega}$

$\Rightarrow T=\dfrac{2\pi\times2}{\pi}\\\Rightarrow T=4\space s$