Calculate the de-Broglie wavelength of a proton whose kinetic energy is equal to the rest mass energy of an electron (mass of proton is 1836 times that of electron).
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Expert's answer
2021-03-02T18:04:55-0500
The rest mass energy of electron is E0=mec2. The de-Broglie wavelength is
λB=pph.
The momentum of proton is pp=mpv, the kinetic energy is Ek=2mpv2, so mpv=mp⋅mp2Ek=2mpEk=2mpmec2=2mpmec. Therefore, the de-Broglie wavelength is λB=2mpmech=2⋅1836⋅(9.1⋅10−31kg)2⋅3⋅108m/s6.63⋅10−34J⋅s=4⋅10−14m.
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