Find the lowest energy of an electron confined in a cubical box of each side 1 Å?
E=h28ma2,E=\frac{h^2}{8ma^2},E=8ma2h2,
E=(6.63⋅10−34)22⋅9.11⋅10−31⋅10−20≈24.12⋅10−18 J=24.12 aJ.E=\frac{(6.63\cdot 10^{-34})^2}{2\cdot 9.11\cdot 10^{-31}\cdot 10^{-20}}\approx24.12\cdot 10^{-18} ~\text{J}=24.12~\text{aJ}.E=2⋅9.11⋅10−31⋅10−20(6.63⋅10−34)2≈24.12⋅10−18 J=24.12 aJ.
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