Answer to Question #167706 in Quantum Mechanics for Sherine Horo

Quantum Mechanics

Question #167706

Find the lowest energy of an electron confined in a cubical box of each side 1 Å?

Expert's answer

"E=\\frac{h^2}{8ma^2},"

"E=\\frac{(6.63\\cdot 10^{-34})^2}{2\\cdot 9.11\\cdot 10^{-31}\\cdot 10^{-20}}\\approx24.12\\cdot 10^{-18} ~\\text{J}=24.12~\\text{aJ}."

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