Question #167706

Find the lowest energy of an electron confined in a cubical box of each side 1 Å?


1
Expert's answer
2021-03-01T12:38:38-0500

E=h28ma2,E=\frac{h^2}{8ma^2},

E=(6.631034)229.111031102024.121018 J=24.12 aJ.E=\frac{(6.63\cdot 10^{-34})^2}{2\cdot 9.11\cdot 10^{-31}\cdot 10^{-20}}\approx24.12\cdot 10^{-18} ~\text{J}=24.12~\text{aJ}.


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