A stream of electrons, each of energy 𝑬 = 𝟑𝒆𝑽 is incident on a potential of height 𝑽𝟎 = 𝟒𝒆𝑽 . The width of the barrier is 20Å. Calculate the percentage transmission of the beam through this barrier.?
E=3eVE=3eVE=3eV
Vo=4eVV_{o}=4eVVo=4eV
L=20Ao=20×10−10mL=20A^o=20\times10^{-10}mL=20Ao=20×10−10m
αL=2m(Vo−E)ℏL m=9.1×10−31kg\alpha L=\sqrt{\dfrac{2m(V_o-E)}{\hbar}}L\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space m=9.1\times10^{-31}kgαL=ℏ2m(Vo−E)L m=9.1×10−31kg
αL=10.23\alpha L=10.23αL=10.23
Transmittance, T=16×34×(1−34)×e−2αLT=16\times\dfrac{3}{4}\times(1-\dfrac{3}{4})\times e^{-2\alpha L}T=16×43×(1−43)×e−2αL
T=3.90×10−9T=3.90\times10^{-9}T=3.90×10−9
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