Answer to Question #167446 in Quantum Mechanics for Kipkirui Emmanuel

Question #167446

An 800N elevator hangs by a steel cable for which the allowable stress is 1.2×10⁸ n/m².What is the minimum diameter required if the elevator accelerates upwards at 1.5m/s²?


1
Expert's answer
2021-03-02T18:09:47-0500
T=ma+W=agW+WT=PA=0.25πd2PagW+W=0.25πd2P1.59.8800+800=0.25π(1.2108)d2d=3.1103 mT=ma+W=\frac{a}{g}W+W\\T=PA=0.25\pi d^2P\\\frac{a}{g}W+W=0.25\pi d^2P\\ \frac{1.5}{9.8}800+800=0.25\pi (1.2\cdot10^{8})d^2\\d=3.1\cdot10^{-3}\ m


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