If an amplifier working with ±5V DC power supplies, requires a
minimum output voltage of 3V across a load resistance of 100 ohms,
calculate the minimum current to be drawn from the power supply, if
the efficiency of the amplifier is 35%.
"\\eta=\\frac{U_mI_m}{U_mI_m+\\frac{U^2}{R}},\\implies" "I_m=\\frac{\\eta U^2}{(1-\\eta)U_mR},"
"I_m=\\frac{0.35\\cdot 5^2}{0.65\\cdot 3\\cdot 100}=44.9~mA."
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