Question #160178
Fission of one nucleus uranium-235 yields an average of approximately 200 MeV. What mass of uranium produces the energy of 3.30 x 10^10 J in fission?
1
Expert's answer
2021-02-22T10:29:05-0500

If one nucleus yields 200MeV=3.21011J200MeV=3.2\cdot10^{-11}J, then we need N=3.310103.210111.031021N=\frac{3.3\cdot 10^{10}}{3.2\cdot10^{-11}}\approx 1.03\cdot10^{21} of nuclei. The molar mass of U-235 is 235g/mol235 g/mol, where 1mol1 mol contains 6.0210236.02\cdot10^{23} atoms/molecules. Therefore the mass of NN U-235 nuclei (the mass of a nucleus is approximately the mass of an atom, as the electron mass is neglected) is 2351.0310216.0210230.4g235\cdot\frac{1.03\cdot10^{21}}{6.02\cdot10^{23}}\approx 0.4 g.


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