Hypervelocity bullet used in 0.22 long rifle usually weigh around 2.1 g and can have a speed of 550 m/s. what must be the speed of a 75 kg man to match the momentum of this bullet?
Answer
Using momentum conservation theory
"mv=m'v'"
m,v for man and rest for gun notation.
Putting all given value in question
And then velocity of man is
"v=\\frac{m'v'}{m}=\\frac{0.0021\\times550}{50}\\\\=0.231m\/s"
Comments
Leave a comment