Question #152408
Expectation valu of (momentum)^4 in one dim linear harmonic oscilator
1
Expert's answer
2020-12-23T07:35:09-0500

Answer

n-th state of one dim linear harmonic oscilator is given by

n>=(α2nn!π)1/2eα2x2/2Hn(αx)|n>=(\frac{\alpha}{2^n n! \sqrt{\pi}}) ^{1/2}e^{-\alpha^2 x^2/2} H_n(\alpha x)

Now

Expectation value of momentum^4

<p4>=<np4n><nn><p^4>=\frac{<n|p^4n>}{<n|n>}

Putting

P=i2mP=\frac{-i\hbar}{2m} And state n

So expectation value is

<p4>=(mω2)2(6n2+6n+3)<p^4>=(\frac{\hbar m\omega}{2}) ^2(6n^2+6n+3)


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