According to the Wien's displacement law,
where b ≈ 2898 μm⋅K is Wien's constant.
Therefore,
T=bλpeak=2898⋅103 nm⋅K500 nm=5796 K\displaystyle T=\frac{b}{\lambda_{peak}} = \frac{2898\cdot 10^{3} \;nm\cdot K }{500 \; nm} = 5796 \;KT=λpeakb=500nm2898⋅103nm⋅K=5796K
Answer: 5796 K.
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