According to the Wien's displacement law,
where b ≈ 2898 μm⋅K is Wien's constant.
Therefore,
"\\displaystyle T=\\frac{b}{\\lambda_{peak}} = \\frac{2898\\cdot 10^{3} \\;nm\\cdot K }{500 \\; nm} = 5796 \\;K"
Answer: 5796 K.
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