Solution
According to given data
Pressure P = ( ρgh )1/2
Left hand side
pressure=Nm2=Kg−mm2−sec2=Kgm−sec2pressure=\frac{N}{m^2}= \frac{Kg - m}{m^2- sec^2}\\=\frac{Kg }{m-sec^2}pressure=m2N=m2−sec2Kg−m=m−sec2Kg
Now Right hand side
ρgh=Kgm3.msec2.m\rho gh=\frac{Kg }{m^3}.\frac{m }{sec^2}.mρgh=m3Kg.sec2m.m
=Kgm−sec2\frac{Kg }{m- sec^2}m−sec2Kg
So left and right hand side are equal in dimensional.
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