a)
The work function is
"W=2.7 eV=4.32 \\times10^{-19} J"
b)
The threshold frequency is
"f=\\frac{W}{h}=\\frac{4.32 \\times10^{-19}}{6.626 \\times10^{-34}}=6.52 \\times 10^{14} Hz"
c)
The maximum wavelength is
"\\lambda =\\frac{hc}{W} =\\frac{(6.626 \\times10^{-34})(3.0 \\times10^{8})}{4.32 \\times10^{-19}}=460 nm"
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