a)
The work function is
W=2.7eV=4.32×10−19JW=2.7 eV=4.32 \times10^{-19} JW=2.7eV=4.32×10−19J
b)
The threshold frequency is
f=Wh=4.32×10−196.626×10−34=6.52×1014Hzf=\frac{W}{h}=\frac{4.32 \times10^{-19}}{6.626 \times10^{-34}}=6.52 \times 10^{14} Hzf=hW=6.626×10−344.32×10−19=6.52×1014Hz
c)
The maximum wavelength is
λ=hcW=(6.626×10−34)(3.0×108)4.32×10−19=460nm\lambda =\frac{hc}{W} =\frac{(6.626 \times10^{-34})(3.0 \times10^{8})}{4.32 \times10^{-19}}=460 nmλ=Whc=4.32×10−19(6.626×10−34)(3.0×108)=460nm
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