Question #139011

A small body starts falling onto the Sun from a distance equal to the radius of the Earth orbit. The initial velocity of the body is equal to zero in the heliocentric reference frame. Making use of Kepler s laws, find how long the body will be falling.

Expert's answer

Solution

Here according to question semi major axis a=R/2

Hence τ\tau is the time of fall then

(2τT)2=(R/2R)3(\frac{2\tau}{T}) ^2=(\frac{R/2}{R}) ^3

By using kepler third law. 

So it's become

τ2=T32\tau^2=\frac{T}{32}

τ=36542=64.5\tau=\frac{365}{4\sqrt{2}}=64.5 days


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