Question #138084

A cannon of mass M starts sliding freely down a smooth inclined plane at an angle α to the horizontal. After the cannon covered the distance l, a shot was fired, the shell leaving the cannon in the horizontal direction with a momentum p. As a consequence, the cannon stopped. Assuming the mass of the shell to be negligible, as compared to that of the cannon, determine the duration of the shot.

Expert's answer

Solution

According to question velocity of cannon is2glsinα\sqrt{2gl \sin\alpha} down to inclined plane. using linear impulse momentum theorem

Δpx=Fxdt\Delta p_x=F_xdt

    pcosαM2glsinα\implies p\cos \alpha-M\sqrt{2gl\sin\alpha}

=MgsinαΔt=Mg\sin \alpha\Delta t


Δt=pcosαM2glsinαMgsinα\Delta t=\frac{p\cos \alpha-M\sqrt{2gl\sin\alpha}}{Mg\sin \alpha}


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