Solution
Energy of electron E=0.511×106eVE=0.511\times10^6eVE=0.511×106eV
Momentum of electron
p=600×103eV/cp=600\times10^3 eV/cp=600×103eV/c
Phase velocity is given by
vp=Ep=0.511×106eV600×103eV/cv_p=\frac{E}{p}=\frac{0.511\times10^6eV}{600\times10^3 eV/c}vp=pE=600×103eV/c0.511×106eV
vp=0.255×109m/sv_p=0.255\times10^9m/svp=0.255×109m/s
And
Group velocity is given by
vg=c2vp=9×10160.255×109v_g=\frac{c^2}{v_p}=\frac{9\times10^{16}}{0.255\times10^9}vg=vpc2=0.255×1099×1016
vg=3.53×108m/sv_g=3.53\times10^8 m/svg=3.53×108m/s
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment