Answer to Question #137914 in Quantum Mechanics for Ria

Question #137914
Momentum of an election is 600kev/c the group velocity and phase velocity of the electron is
1
Expert's answer
2020-10-12T07:44:10-0400

Solution

Energy of electron E=0.511×106eVE=0.511\times10^6eV

Momentum of electron

p=600×103eV/cp=600\times10^3 eV/c

Phase velocity is given by

vp=Ep=0.511×106eV600×103eV/cv_p=\frac{E}{p}=\frac{0.511\times10^6eV}{600\times10^3 eV/c}

vp=0.255×109m/sv_p=0.255\times10^9m/s

And

Group velocity is given by

vg=c2vp=9×10160.255×109v_g=\frac{c^2}{v_p}=\frac{9\times10^{16}}{0.255\times10^9}

vg=3.53×108m/sv_g=3.53\times10^8 m/s


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