Pclassical=1π∫−11e−ξ2dξP_{classical}=\frac{1}{\sqrt\pi}\intop_{-1}^{1}e^{-\xi^2}d\xiPclassical=π1∫−11e−ξ2dξ
This integral is the error function, so we find;
Pclassical=erf(1)=0.8427P_{classical}=erf(1)=0.8427Pclassical=erf(1)=0.8427
The probability of being outside the classical region is then;
1−Pclassical=0.15731-P_{classical}=0.15731−Pclassical=0.1573
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment