Question #133849

A ball is launched from ground level with an initial upwards velocity of 20 m/s and an initial horizontal velocity of 30 m/s. How far from its starting position does the ball land assuming the ground is level?

Expert's answer

Assume that vertical velocity is u,u,

horizontal is vv.

The time for the ball to go up and down:


t=2⋅ugt=2\cdot\frac{u}{g}

The distance the ball will travel horizontally is


R=t⋅v=2vug=122 m.R=t\cdot v=\frac{2vu}{g}=122\text{ m}.
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