. A thermal neutron has a speed of ν that corresponds to room temperature T=300K. What is the wavelength of a thermal neutron ?
Given
Temperature is T=300KT=300 KT=300K
Mass of neutron is m=1.67×10−27kgm=1.67\times10^{-27} kgm=1.67×10−27kg
The wavelength of thermal neutrons is
λ=h3mkBT\lambda=\frac{h}{\sqrt{3mk_BT} }λ=3mkBTh
=6.626×10−343(1.67×10−27)(1.38×10−23)(300)=\frac{6.626\times10^{-34}}{\sqrt{3(1.67\times10^{-27})(1.38\times10^{-23})(300)} }=3(1.67×10−27)(1.38×10−23)(300)6.626×10−34
=1.45×10−10m=1.45\times10^{-10} m=1.45×10−10m
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment