Question #123229
Q#1 An electron in a circular orbit about a proton can be described by classical mechanics if its angular momentum L is very much greater than h. Show that this condition is satisfied if the radius of the orbit r is very much greater than the Bohr radius a0 , i.e if

r>>a0 = 4πϵh2/e2me
1
Expert's answer
2020-06-22T11:11:55-0400

Let us consider the circular motion of electron, so the acceleration is

a=v2r.a =\dfrac{v^2}{r}. The force due to which the motion exists is F=14πε0e2r2.F = \dfrac{1}{4\pi\varepsilon_0}\cdot\dfrac{e^2}{r^2}. Therefore, v2=e24πε0mer.v^2 = \dfrac{e^2}{4\pi\varepsilon_0m_er}.

The angular momentum is L=mevr.L=m_evr .

If Lh,L \gg h, or L2h2,      me2v2r2h2,      me2e24πε0merr2h2,      rh24πε0mee2L^2\gg h^2, \;\;\; m_e^2v^2r^2 \gg h^2, \;\;\; m_e^2\cdot \dfrac{e^2}{4\pi\varepsilon_0m_er}\cdot r^2 \gg h^2, \;\;\; r \gg \dfrac{h^24\pi\varepsilon_0}{m_ee^2} .


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