Question #122039
Suppose an atom of Osmium at rest emits an X-ray photon of energy 6.8 keV. Calculate the “recoil” momentum and kinetic energy of the atom.
1
Expert's answer
2020-06-15T09:49:02-0400

As,system has initial momentum is zero and no external interaction there,Momentum of the system is conserved.

Therefore, momentum

pos+pγ=0p_{os}+p_{\gamma}=0 ​

We have given that, emitted photon has energy is 8.6keV8.6keV

Since,

Eγ=pγc    pγ=Eγc=8.6keV/cE_{\gamma}=p_{\gamma}c\\ \implies p_{\gamma}=\frac{E_{\gamma}}{c}=8.6keV/c


Thus,

pos=8.6keV/cp_{os}=-8.6keV/c

Kinetic energy is

K=p22mK=\frac{p^2}{2m}


Hence,

Kos=2.088×104eVK_{os}=2.088\times 10^{-4}eV


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