As,system has initial momentum is zero and no external interaction there,Momentum of the system is conserved.
Therefore, momentum
pos+pγ=0
We have given that, emitted photon has energy is 8.6keV
Since,
Eγ=pγc⟹pγ=cEγ=8.6keV/c
Thus,
pos=−8.6keV/c
Kinetic energy is
K=2mp2
Hence,
Kos=2.088×10−4eV
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