Question #122039

Suppose an atom of Osmium at rest emits an X-ray photon of energy 6.8 keV. Calculate the “recoil” momentum and kinetic energy of the atom.

Expert's answer

As,system has initial momentum is zero and no external interaction there,Momentum of the system is conserved.

Therefore, momentum

pos+pγ=0p_{os}+p_{\gamma}=0 ​

We have given that, emitted photon has energy is 8.6keV8.6keV

Since,

Eγ=pγc    pγ=Eγc=8.6keV/cE_{\gamma}=p_{\gamma}c\\ \implies p_{\gamma}=\frac{E_{\gamma}}{c}=8.6keV/c


Thus,

pos=8.6keV/cp_{os}=-8.6keV/c

Kinetic energy is

K=p22mK=\frac{p^2}{2m}


Hence,

Kos=2.088×104eVK_{os}=2.088\times 10^{-4}eV


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