Question #120613

how much heat is needed to melt 1.5kg of ice and then to rise the temperature of the resulting water 500c?

Expert's answer

The amount of heat required to melt ice and raise the temperature of water ToCT^oC is

Q=mLf+mcΔTQ=mL_f+mc\Delta T

Here m=1.5kgm=1.5 kg

Lf=3.33105J/kgL_f=3.33*10^5 J/kg is Latent heat of fusion of ice.

c=4186J/kg.oCc=4186 J/kg.^oC is heat capacity of water.

ΔT=50oC0oC=50oC\Delta T=50 ^oC-0^oC=50^oC

So,

Q=(1.50)[3.33105+(4186)(50)]=8.13105JQ=(1.50)[3.33*10^5 +(4186)(50)]=8.13*10^5 J


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