Answer to Question #120613 in Quantum Mechanics for usman

Question

how much heat is needed to melt 1.5kg of ice and then to rise the temperature of the resulting water 500c?

Answer 1

The amount of heat required to melt ice and raise the temperature of water $T^oC$ is

$Q=mL_f+mc\Delta T$

Here $m=1.5 kg$

$L_f=3.33*10^5 J/kg$ is Latent heat of fusion of ice.

$c=4186 J/kg.^oC$ is heat capacity of water.

$\Delta T=50 ^oC-0^oC=50^oC$

So,

$Q=(1.50)[3.33*10^5 +(4186)(50)]=8.13*10^5 J$