Answer to Question #119182 in Quantum Mechanics for gly

Question #119182
A 1 hp motor rotates 1200 rpm.How much torque can it exert?
1
Expert's answer
2020-06-01T14:27:26-0400

Toque

(T)=Power(HP)×5252RPM(T) = \frac{Power(HP)\times 5252 }{RPM}


(T)=1×52521200(T) = \frac{1 \times 5252 }{1200}


(T)=4.38lbft=5.94Nm(T) = 4.38 lb-ft = 5.94 N-m







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