Kinetic energy of the emitted electron is given by
"T_e=\\frac{\\hbar c}{\\lambda}-4.7>0" "\\lambda=2000 \\colon T_e=1.58 \\cdot 10^{-19} \\frac{kg \\cdot m^2}{s^2}-4.7 \\cdot 1.6 \\cdot 10^{-19} \\frac{kg \\cdot m^2}{s^2}\\\\ \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=(1.58-7.52)\\cdot 10^{-19} J<0"
Obviously, for "\\lambda=5000 \\colon T_e<0".
Hence, the energy of photons is too low for electrons to leave the surface.
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