Question #109506
An electron has the following wave function:

ψ(x)=A(e^-x)(1-e^-x)


Determine
i) the normalization constant A, and
ii) the expectation value of x .
1
Expert's answer
2020-04-15T10:20:51-0400

The wave function of an electron

ψ(x)=Aex(1ex).\psi(x)=Ae^{-x}(1-e^{-x}).

(i) The normalization condition

1=0ψ(x)2dx1=A20e2x(1ex)2dx=A212A=23.1=\int_{0}^{\infty}|\psi(x)|^2dx\\ 1=A^2\int_{0}^{\infty}e^{-2x}(1-e^{-x})^2dx=\frac{A^2}{12}\\ A=2\sqrt{3}.

(ii) The expectation value of xx

x=120xe2x(1ex)2dx=1312=1.08\lang x\rang =12\int_{0}^{\infty}xe^{-2x}(1-e^{-x})^2dx=\frac{13}{12}=1.08

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