Question

A photon and an electron each have an energy of
6×10^3.
What are their
wavelengths? Which of these would you use to probe atomic structures?

Answer 1

$E=6\cdot10^3$ $eV$

$\lambda=\frac{h}{\sqrt{2mE}}$

For electron

$\lambda_e=\frac{h}{\sqrt{2mE}}=\frac{6.62\cdot10^{-34}}{\sqrt{2\cdot 9.1\cdot10^{-31}\cdot 1.6\cdot10^{-19}\cdot 6000}}=1.58\cdot10^{-11} m=15.8$ $pm$

For proton

$\lambda_p=\frac{h}{\sqrt{2mE}}=\frac{6.62\cdot10^{-34}}{\sqrt{2\cdot 1.67\cdot10^{-27}\cdot 1.6\cdot10^{-19}\cdot 6000}}=1.17\cdot10^{-12} m=1.17$ $pm$

I would use electrons to probe atomic structures.