Question #101306

An electron is emitted from the surface of the big metallic plane perpendicular to it with initial velocity 0 v , How far from the plane the electron may manage to move in two cases: 1) the electron moves in the braking electric field E , 2) additionally to the electric field E, there is a magnetic field B, directed parallel to the surface of the plane

Expert's answer

1)

the kinetic energy of the electron is numerically equal to the work of the forces of the electric field

mv22=eEd(1)\frac{mv^2}{2}=eEd (1)

Where m is the mass of electron, e is the charge of electron

Using (1) we get

d=mv2eEd=\frac{mv^2}{eE}


2) the magnetic force is always perpendicular to the direction of displacement and magnetic forces do not do any work

d=mv2eEd=\frac{mv^2}{eE}


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