classical acoustic guitar string has an active length (the so-called “scale” length) of 66 cm.
a) By how much must the string be shortened in order to increase its pitch by a perfect fifth? (Equivalently, what must the string’s active length become
1
Expert's answer
2019-12-04T08:05:43-0500
Frequency "\\nu = \\frac{v}{\\lambda} = \\frac{v}{2l}."
If "\\nu_1 = 1.2\\nu", then "l_1 = \\frac{v}{2\\nu_1} = \\frac{l}{1.2}" , therefore "\\Delta l = l(1 - \\frac{1}{1.2}) = 11 sm."
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