Answer to Question #99565 in Physics for Muiz

Question

A uniform rod of 1.5m in equilibrium on a pivot where AP represent the rod. If AP=40m,find mass of the rod (g=10m/s2

Answer 1

For the equilibrium:

$$7(0.4)=m(10)(0.5(1.5)-0.4)$$

$$m=0.8\ kg$$