Question #99125
A mass of 5KG is on top of a building of heights 10M calculate its potential energy the mass then falls at a speed of 8M/S in 4 seconds find its KE and momentum P what is the force and impulse the mass transfers to the ground
1
Expert's answer
2019-11-21T10:06:37-0500

Potential energy:


E=mgh=(5)(9.8)(10)=490 JE=mgh=(5)(9.8)(10)=490\ J

KE=0.5mv2=0.5(5)(8)2=160 jKE=0.5mv^2=0.5(5)(8)^2=160\ j

P=mv=(5)(8)=40kgmsP=mv=(5)(8)=40\frac{kgm}{s}

The impulse the mass transfers to the ground:


I=P=40kgmsI=P=40\frac{kgm}{s}

The force:


F=It=404=10 NF=\frac{I}{t}=\frac{40}{4}=10\ N


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