1) The resistance can be found according to Ohm's law:
R=V/I=120/12=10 Ω. 2) The speed is
v=λ ν=0.005⋅10000=50 m/s. 3) The electric force can be found according to Coulomb's law:
F=kr2q1q2=9⋅1091525⋅5=1⋅109 N. 4) The work done while the mass was falling from 2 meters:
W=mgh=m⋅9.8⋅2=19.6m. While the body was falling within 11 s:
W=mgh=mg⋅gt2/2=m(gt)2/2=5810m. 5) The potential energy is
PE=mgh=5⋅9.8⋅10=490 J. The kinetic energy and momentum are:
KE=mv2/2=160 J.p=mv=40 kg-m/s. the force and impulse:
F=Δp/Δt=(40−0)/4=10 N.J=Δp=40−0=40 kg-m/s.
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