Question #98916
A 2.2kg block being pulled across a table by a horizontal force of 60N also experiences a frictional force of 24N. What is the acceleration of the block?
1
Expert's answer
2019-11-18T11:24:43-0500

According to Newton's second law, acceleration is a=Fma = \frac{F}{m}, where FF is the net force, acting on an object, and mm is the mass of the object. Frictional force FfF_f is directed in the opposite direction to the applied horizontal force F=60NF = 60 N , hence their net is FFf=36NF - F_f = 36 N. Hence, the acceleration is a=36N2.2kg16.37ms2a = \frac{ 36 N}{2.2 kg} \approx 16.37 \frac{m}{s^2}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS